Let v be a superadditive characteristic function for a simple game. Show that if v(S) = 0 and A ⊂ S then v(A) = 0 and if v(S) = 1 and S ⊂ A then v(A) = 1

Let v be a superadditive characteristic function for a simple game. Show that if v(S) = 0 and A ⊂ S then v(A) = 0 and if v(S) = 1 and S ⊂ A then v(A) = 1

Let v be a superadditive characteristic function for a simple game. Show that if v(S) = 0 and A ⊂ S then v(A) = 0 and if v(S) = 1 and S ⊂ A then v(A) = 1

Let v be a superadditive characteristic function for a simple game. Show that if v(S) = 0 and A ⊂ S then v(A) = 0 and if v(S) = 1 and S ⊂ A then v(A) = 1