Numerical Analysis

Assignment 3 – Due Monday Feb. 22
1. [Exercise Set 3.1, Q6] Use appropriate Lagrange interpolating polynomials of degrees one, two,
and three to approximate each of the following (by hand):
(b) !(0) if!(−0.5) = 1.93750, !(−0.25) = 1.33203, !(0.25) = 0.800781,
!(0.5) = 0.687500
(d) !(0.25) if!(−1) = 0.86199480, !(−0.5) = 0.95802009, !(0) = 1.0986123,
!(0.5) = 1.2943767
2. [Exercise Set 3.2, Q6] Neville’s method is used to approximate!(0.5), giving the following table.
Determine1
2 = !(0.7).
3
4 = 0 14 = 0
3
5 = 0.4 15 = 2.8 14,5 = 3.5
3
2 = 0.7 12 15,2 14,5,2 = 27/7
3. [Exercise Set 3.3, Q15] The Newton forward divided-difference formula is used to approximate
!(0.3) given the following data.
x 0.0 0.2 0.4 0.6
f(x) 15.0 21.0 30.0 51.0
Suppose it is discovered that !(0.4) was understated by 10 and !(0.6) was overstated by 5. By
what amount should the approximation to !(0.3) be changed?
4. [Exercise Set 3.4, Q2]
(a) Use Theorem 3.9 or Algorithm 3.3 to construct an approximating polynomial (by hand) for
the following data.
x f(x) f’(x)
0.1 -0.29004996 -2.8019975
0.2 -0.56079734 -2.6159201
0.3 -0.81401972 -2.9734038
(b) Use Theorem 3.9 or Algorithm 3.3 to construct an approximating polynomial (by MAPLE or
other software, program) for the data listed in above table.
5. [Exercise Set 3.5, Q3 & Q5]
(a) Construct the natural cubic spline for the following data.
x f(x)
8.3 17.56492
8.6 18.50515
(b) The data in above table were generated using !(3) = 3 ln (3). Use the cubic splines
constructed in 5(a) for the given value of x to approximate !(0.9) and !′(0.9), and calculate the
actual error.

TAKE ADVANTAGE OF OUR PROMOTIONAL DISCOUNT DISPLAYED ON THE WEBSITE AND GET A DISCOUNT FOR YOUR PAPER NOW!

READ ALSO :   nutrition