Following the same procedure as that for player I, look atE(i, Y),i = 1, 2. with Y = (y, 1 − y). Graph the lines E(1, Y) = y + 4(1 − y) and E(2, Y) = 3y + 2(1 − y), 0 ≤ y ≤ 1. Now, how does player II analyze the graph to find Y∗?

Following the same procedure as that for player I, look atE(i, Y),i = 1, 2. with Y = (y, 1 − y). Graph the lines E(1, Y) = y + 4(1 − y) and E(2, Y) = 3y + 2(1 − y), 0 ≤ y ≤ 1. Now, how does player II analyze the graph to find Y∗?

Following the same procedure as that for player I, look atE(i, Y),i = 1, 2. with Y = (y, 1 − y). Graph the lines E(1, Y) = y + 4(1 − y) and E(2, Y) = 3y + 2(1 − y), 0 ≤ y ≤ 1. Now, how does player II analyze the graph to find Y∗?
Following the same procedure as that for player I, look atE(i, Y),i = 1, 2. with Y = (y, 1 − y). Graph the lines E(1, Y) = y + 4(1 − y) and E(2, Y) = 3y + 2(1 − y), 0 ≤ y ≤ 1. Now, how does player II analyze the graph to find Y∗?