Probability of specific combination of offspring
The probability of a specific combination of offspring = { n! / (w! x!)} multiplied by pw multiplied by q x. Where n, w and x refer to numbers of observations (e.g. progeny) and p and q refer to the probability of the respective observation. A man and a woman are heterozygous for cystic fibrosis, an autosomal recessive disorder: ie., both are carriers (genotype Aa).
_______: (2 pts) what is the probability that, if they have 5 children by separate conceptions and births, 1 will have CF and 4 will be normal? Show your work.