Excavation
Lab Assignment #2
CEMT 28000 – Quantity Survey
Problems
1. Our foundation requires that we drill fifty-eight (58) 2’-7” diameter holes into the earth to accommodate our special footing. On average each hole will be 14’-0” deep. Because they’re drilled holes, we don’t need to worry about repose.
Contractor Assumptions
Swell factor: 10% Truck capacity: 7 CY
a. How many dump truck loads are required to move the excavated earth off the site? (EA)
2. The construction drawings indicate a 6” slab-on-grade (S.O.G.) which measures 223’-3”L x 110’-5”W. It requires 5” of compacted fill beneath it.
Contractor Assumptions
Compaction factor: 95%
Truck capacity: 10 CY
a. How many dump truck loads of compacted fill do you need? (EA)
3. Refer to Figure 1. The excavation is a simple trench.
a. How much earth must be stored on-site as the result of the excavation for the footing? (CY)
Contractor Assumptions
Swell Factor: 10%
Backhoe bucket width: 24”
Working space: none required
Repose angle: not applicable
4. Refer to Figure 2. Utilizing the information provided on the contour plan, calculate the total fill, total cut and the net difference for the cells A, B, C, and D. Reference the take-off sheet shown in Chapter 2, Figure 2 (p. 17) as an example layout. However, use four
(4) points, not five (5). Also, while the book indicates creating a separate table for cut and fill, you may combine cut and fill into one table using + (fill) and – (cut) signs.
a. Total cut (CY)
b. Total fill (CY)
c. Net difference (CY)
1 of 7
Lab Assignment #2
CEMT 28000 – Quantity Survey
Fall 2015
5. Using the attached Medical Office Building drawings (Drawings 5, 6, & 7), calculate the total number of dump trucks required to remove the dirt for the wall footing. Assume you need to excavate down to the bottom of the footing for the entire trash enclosurefootprint.
Contractor Assumptions
Swell factor: 15%
Angle of repose: 1:1 (45d) Dump truck capacity: 10 CY Working space: 2’-0”
Top of slab = top of grade
Contract Document Information
Top of foundation (T.O.F) elevation: +104.833’ Top of grade elevation: +104.333’
6. Refer to the Foundation Plan for the Public Library (Sheet S2.1) and Section 7/S2.1 (below). Determine the amount of excavation required for the entire building footprint. Tip: the building plan is essentially a right triangle. The excavation depth is the same for the entire footprint. (CY)
Contractor Assumptions
Swell factor: 15%
Angle of repose: 1:1 (45d) Working space: 1’-0”
Excavation depth = bottom of footing
Contract Document Information
Top of slab elevation: +100.0’ Top of grade elevation: +99.333’
Overall exterior dimensions align with face of foundation wall
2 of 7
Lab Assignment #2
CEMT 28000 – Quantity Survey
Fall 2015
Deliverables
Submit the following (one (1) PDF file) via Canvas / Assignments:
1. Fully executed class standard take-off sheet modified as needed for this assignment.
2. Formulas sheet.
Due
Refer to Canvas / Assignments.
Point Value
Points
Assignment Component possible Remarks
Calculations 30 5 points / problem. Accuracy w/i acceptable
percentage (Problems 1 – 5).
Format 5 Proper layout, legibility, instructions, formatting
TOTAL 35
ESTIMATE WORK SHEET
Assignment # Lab #1 Estimate No.
Lab Day Tuesday Sheet No.
Student Sabrin Alaklouk Date 9/1/2015
Topic Fundamentals By Checked
Problem Sub (Answer)
Number Description Comments / Calculations / Logic Totals Quantity Units
QTY LF/EA feet inches
1a Rebar Rebar quantity X piece length 2345 5.667 13289.115 13289.12 LF 1 1 0.083
LF LBS/FT 2 2 0.167
1b Rebar total weight ( lbs) Total length x pounds/ foot 13289.115 0.438 5820.63237 5820.63237 LBS 3 3 0.250
LBS LBS/TON 4 4 0.333
1c Rebar Total weight (TN) Pounds/ Ton Conversion 5820.632 2000.000 2.910316 2.91 TONS 5 5 0.417
6 6 0.500
length width height 7 7 0.583
2 Concrete required to fill the slab Length x width x height 63.416 85.196 0.333 1799.128915 66.6344 CY 8 8 0.667
9 9 0.750
length width 10 10 0.833
3a The floor area width x length 23.583 11.666 275.119278 275.119278 SF 11 11 0.917
length LF width LF 12 12 1.000
3b The total length of the walls 2 ( length + width ) 23.583 11.666 70.498 70.498 LF 13
length width 14
3c The total wall area width x length 23.583 8.000 188.664 564 SF 15
16
short length whole length 17
4 The amount of the fences the total length of the fence/ short length 5feet = the result + 1 5.000 1322.000 264.400 1.000 265.400 265.400 fence posts 18
19
r^2 h
5a The total amount of concrete v= π x r^2 x h 0.340 11.166 11.93632927 1.5274 CY
Volume QTY
5b The total amount of concrete in 60 colm the volume x 60 1.527 60.000 91.644 32.503 CY
width length
6a The area of the propert width x length 211.910 483.670 102494.5097 102494.5097 SF
Area Acres
6b The amount of the acres in the property area / acres 102494.510 43560.000 2.352950184 2.352950184 EA
Length Width Height
6c The amount of the top soil that should be removed V= L X W X H 483.670 211.910 0.333 34130.67173 34130.67173 CF
Area
6d The amount of the fence posts around the property Area of the property + 1 102494.510 102495.510 102495.510 EA
TOTAL FENCE
6e The extra posts that we need to buy the total number of the fence pots multiplied by 0.1 102495.510 10249.55097 10249.55097 EA
Area SF for one GAL
7a The amount of the gallons of black tap we need area/ the 220 SF that is covered by one gallon of black tap sealer 33410.000 220.000 151.8636364 151.8636364 GAL
Total GAL
7b The amount of the container we need to buy The total amount of GAL/ 5 gallon buckets 151.864 30.37272727 30.37272727 EA
π R^2 Height CF CY
8a The amount of the earth that must be removed V= π X R^2 X H 3.142 361.000 1325.000 1502701.037 55655.641
Width Length
9a Lineal feet of the foundation wall Area= W X L 29.916 34.666 1037.068056 1037.068056 SF or LF
Height Width Length CF CY
9B The amount of the concrete required to fil the wall V= H X W X L 1.000 4.000 1037.068 4148.272224 153.639
10 the sympol means Demolition Not